10+-2b+b^2=5

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Solution for 10+-2b+b^2=5 equation:


Simplifying
10 + -2b + b2 = 5

Solving
10 + -2b + b2 = 5

Solving for variable 'b'.

Reorder the terms:
10 + -5 + -2b + b2 = 5 + -5

Combine like terms: 10 + -5 = 5
5 + -2b + b2 = 5 + -5

Combine like terms: 5 + -5 = 0
5 + -2b + b2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-5' to each side of the equation.
5 + -2b + -5 + b2 = 0 + -5

Reorder the terms:
5 + -5 + -2b + b2 = 0 + -5

Combine like terms: 5 + -5 = 0
0 + -2b + b2 = 0 + -5
-2b + b2 = 0 + -5

Combine like terms: 0 + -5 = -5
-2b + b2 = -5

The b term is -2b.  Take half its coefficient (-1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
-2b + 1 + b2 = -5 + 1

Reorder the terms:
1 + -2b + b2 = -5 + 1

Combine like terms: -5 + 1 = -4
1 + -2b + b2 = -4

Factor a perfect square on the left side:
(b + -1)(b + -1) = -4

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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